Write a static method named largerDigits
that accepts two integer parameters a and b and returns a new integer c where each digit of c gets its value from the larger of a's and b's digit in the same place. That is, the ones digit of c is the larger of the ones digit of a and the ones digit of b, and the tens digit of c is the larger of the tens digit of a and the tens digit of b, and so on. You may assume that a and b are positive integers (greater than 0).
For example, suppose a is 603452384 and b is 921782. Their digits would be combined as follows to produce c:
a 603452380
b 920784
------------------
c 952784 (return value)
Notice that if a particular digit place is absent from one number or the other, such as the 603 at the start of a above, no digit is carried over to c. The following table lists some more calls to your method and their expected return values:
Call |
Value Returned |
largerDigits(172, 312) |
372 |
largerDigits(21, 3) |
3 |
largerDigits(90, 38906735) |
95 |
largerDigits(56002, 123321) |
56322 |
largerDigits(11223, 4466) |
4466 |
largerDigits(12345, 12345) |
12345 |
largerDigits(1, 34892) |
2 |
Hint: If you are building a result number, you may need to use Math.pow
or accumulate a multiplier with each digit.
You may not use a String
to solve this problem.